Help with this word problem please! Bayside Insurance offers two health plan A, Giselle would have to pay the first $80.00 of her medical bills, plus 25% of the rest. Under plan B, Giselle would pay the first $90.00 but only 20% of the rest. For what amount of medical bills will plan B save Giselle money? Assume she has over $90 in bills. Giselle would save with plan B if she had more than $? in bills. (Round to the nearest whole number) Thank you!!!

80 + .25x = 90 + .2x

.05x = 10

80 + .25x = 90 + .2x

.05x = 10

Sorry, pushed wrong button.

x = 200

To solve this word problem, we need to compare the total costs of plan A and plan B to determine at what amount of medical bills plan B would save Giselle money.

Let's break down the cost of each plan based on the given information:

Plan A:
- Giselle pays the first $80.00 of her medical bills.
- After that, she pays 25% of the remaining amount.

Plan B:
- Giselle pays the first $90.00 of her medical bills.
- After that, she pays 20% of the remaining amount.

To find the amount of medical bills at which plan B would save Giselle money, we need to set up an equation and solve for that amount.

Let's denote the amount of medical bills as "x".

For plan A, the cost can be calculated as:
$80.00 + (0.25 * (x - $80.00))

For plan B, the cost can be calculated as:
$90.00 + (0.20 * (x - $90.00))

To find the amount of medical bills where plan B saves money, we need to set up the equation:

$90.00 + (0.20 * (x - $90.00)) < $80.00 + (0.25 * (x - $80.00))

Now, let's solve this equation to find the amount of medical bills where plan B saves Giselle money.

$90.00 + (0.20 * (x - $90.00)) < $80.00 + (0.25 * (x - $80.00))

Simplifying the equation:
$90.00 + 0.20x - $18.00 < $80.00 + 0.25x - $20.00

Combining like terms:
$72.00 + 0.20x < $60.00 + 0.25x

Subtracting 0.20x and 0.25x from both sides:
$72.00 - $60.00 < 0.25x - 0.20x

Simplifying:
$12.00 < 0.05x

Dividing both sides by 0.05:
240 < x

Therefore, plan B will save Giselle money if she has more than $240 in medical bills.