Homework Help: physics

Posted by Anonymous on Wednesday, November 16, 2011 at 5:58pm.

A box and its contents have a total mass M = 9 kg. A string passes through a hole in the box, and you pull on the string with a constant force F = 77 N (this is in outer space; there are no other forces acting).

(a) Initially the speed of the box was vi = 5 m/s. After the box had moved a distance w = 2.1 m, your hand had moved an additional distance d = 0.4 (a total distance of w + d), because additional string of length d came out of the box (see figure). What is now the speed vf of the box?

physics - JM, Saturday, November 17, 2012 at 8:17pm
you do
Fd=.5m*vfinal^2-.5m*vinitial^2
solve for vfinal and that is the correct answer.

Answer this Question

Related Questions

physics - A 3.2 kg block sits on a frictionless table that has a hole cut in the...
physics - A mass m1 = 6.0 kg sits on a frictionless table, and rotates at a ...
physics - an air puck of mass 0.347 kg is tied to a string and allowed to ...
Physics B - An air puck of mass 0.289 kg is tied to a string and allowed to ...
AP Physics B - An air puck of mass 0.102 kg is tied to a string and allowed to ...
Physics - An air puck of mass 0.23 kg is tied to a string and allowed to revolve...
Physics - An air puck of mass 0.289 kg is tied to a string and allowed to ...
physics - An air puck of mass m1 = 0.45 kg is tied to a string and allowed to ...
physics - An air puck of mass 0.33 kg is tied to a string and allowed to revolve...
Physics - There is a box resting on a table connected to a second box hanging ...

For Further Reading

First Name:
School Subject:
Answer: