Posted by umesh on Wednesday, November 16, 2011 at 2:29pm.
In biochemistry the molarity of the buffer is the sum of both the acid and the conjugate base. Your post just gives the total but not the breakdown; therefore, I would suggest 50 mL(0.05L) for 0.5M each. That is 0.5 x 0.05 = 0.025 moles.
g each = moles x molar mass.
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