Posted by **Meron** on Wednesday, November 16, 2011 at 9:58am.

Prove the law of sines for triangle ABC i.e sinA/a=sinB/b=sinC/c.0 please help me!!!

## Answer this Question

## Related Questions

- geometry - 1. Triangle ABC has a 63.0-degree angle at B, and side AC is 13.6 cm ...
- geomery - 1. Triangle ABC has a 63.0-degree angle at B, and side AC is 13.6 cm ...
- maths - Choose three options which are true: a) an angle of 150 degrees is ...
- Physics please please help me - Prove the law for triangle ABC i.e sin A/a=sinB/...
- Geometry - ABC is a triangle with area equal to 20 . The incircle of triangle ...
- trig - If A+B+C=^(^=180) prove that sinA + sinB - sinC = 4sinA/2 sinB/2 cosC/2
- geometry - I am studying for my GRE exam into grad school and it's been a very ...
- Pre-Calc - Consider a non-right triangle. a=39 b=25 c = 24.(a,b,c are the sides...
- Physics - My question is How do I calculate the resultant force if I have two ...
- trig - In triangle ABC, sinA=0.6, a=10 and b=7. Find sinB

More Related Questions