The specific heat is 0.80kJ/C. If 1.6MJ of heat are added to a 100-kg granite statue of James Prescott Joule that is originally at 18 degrees C. What is the final tempertaure of the statue?
Well, we have quite a heaty situation here! To find the final temperature of our beloved granite statue of James Prescott Joule, we can use the formula:
Q = mcΔT
Where Q represents the amount of heat added, m is the mass of the object, c is the specific heat capacity, and ΔT is the change in temperature.
First, let's convert the given specific heat from kJ to J:
0.80 kJ = 800 J
Now we can plug in the given values:
1.6 MJ = 1.6 × 10^6 J (converted to J)
m = 100 kg
c = 800 J/C
ΔT = ?
Using the formula, we can rearrange it to solve for ΔT:
ΔT = Q / (mc)
ΔT = (1.6 × 10^6 J) / [(100 kg) × (800 J/C)]
Calculating this, we get:
ΔT = 20 C
So, the final temperature of our granite statue of James Prescott Joule would be 18 degrees C + 20 degrees C = 38 degrees C. James Joule might be feeling a bit warm after all that heat!
To find the final temperature of the granite statue, we can use the formula:
Q = mcΔT
Where:
Q = heat added to the system
m = mass of the object
c = specific heat capacity of the material
ΔT = change in temperature
Given:
Specific heat capacity (c) = 0.80 kJ/C
Heat added (Q) = 1.6 MJ = 1.6 x 10^6 kJ
Mass (m) = 100 kg
Initial temperature (T₁) = 18°C
Let's calculate ΔT first:
Q = mcΔT
ΔT = Q / (mc)
ΔT = (1.6 x 10^6 kJ) / (100 kg × 0.80 kJ/C)
ΔT = 20,000 C
Now, let's find the final temperature (T₂):
T₂ = T₁ + ΔT
T₂ = 18°C + 20,000°C
T₂ = 20,018°C
Therefore, the final temperature of the granite statue is 20,018°C.
To find the final temperature of the granite statue after adding heat, you can use the equation:
Q = m * c * ΔT
Where:
Q is the amount of heat added (in joules),
m is the mass of the substance (in kilograms),
c is the specific heat of the substance (in joules per kilogram per degree Celsius), and
ΔT is the change in temperature (in degrees Celsius).
First, convert the specific heat from kilojoules to joules per kilogram per degree Celsius:
0.80 kJ/C = 0.80 × 1000 J/C = 800 J/C
Next, convert the amount of heat added from megajoules to joules:
1.6 MJ = 1.6 × 10^6 J
Now, rearrange the formula to solve for ΔT:
ΔT = Q / (m * c)
Substitute the values into the formula:
ΔT = (1.6 × 10^6 J) / (100 kg * 800 J/C)
Evaluate the expression:
ΔT = 20 C
Finally, the final temperature of the granite statue can be found by adding the change in temperature to the initial temperature:
Final temperature = Initial temperature + ΔT
Final temperature = 18 C + 20 C
Therefore, the final temperature of the granite statue is 38 degrees Celsius.