can some one explain how to do this
The muzzle velocity of 60g bullet leaving 4kg rifle is 500 m/s towards the east. What is recoil velocity of the rifle?
Try reading your book...
To find the recoil velocity of the rifle, we can use the principle of conservation of momentum. According to this principle, the total momentum before an event is equal to the total momentum after the event, assuming no external forces act on the system.
In this case, the bullet is leaving the rifle, so we can consider the system as the bullet and the rifle. Before the bullet is fired, the system is at rest, so the total momentum is zero. After the bullet is fired, we have to consider the momentum of both the bullet and the rifle.
The momentum of an object is given by the formula:
momentum = mass × velocity
We know the mass of the bullet is 60g = 0.06kg and the velocity of the bullet is 500 m/s towards the east. We also know the mass of the rifle is 4kg. Let's assume the recoil velocity of the rifle is v (unknown value) towards the west.
Using the principle of conservation of momentum, we can write the equation:
(0.06kg × 500 m/s) + (4kg × -v) = 0
Simplifying the equation, we get:
30 kg m/s - 4v = 0
Now we can solve for v by isolating it:
4v = 30 kg m/s
v = 30 kg m/s / 4
v = 7.5 m/s
Therefore, the recoil velocity of the rifle is 7.5 m/s towards the west.