Posted by **farouk** on Wednesday, November 16, 2011 at 3:02am.

Show that the equation;x+3sinx=2 has a root between x=0.4 and x=0.6 using newton raphson's formular only

- calculus -
**Steve**, Wednesday, November 16, 2011 at 5:56am
f(x) = x + 3sinx - 2

f'(x) = 1 + 3cosx

1: f(0.6000000) = 0.2939274

2: f(0.5154411) = -0.0058029

3: f(0.5170484) = -0.0000019

4: f(0.5170490) = -0.0000000

- calculus -
**MathMate**, Wednesday, November 16, 2011 at 1:22pm
Farouk, It would be a good idea to check back the previous posts you have made before reposting. It may save you a long wait.

See answer to your previous post:

http://www.jiskha.com/display.cgi?id=1321390404

## Answer this Question

## Related Questions

- calculus - Show that the equation x+3sinx=2 has a root between 0.4 and 0.6....
- calculus - Use Newton's method to approximate the indicated root of the equation...
- calculus - n(x)=x^5+xe^x, find the real zeroes using newton-raphson methodology.
- Math/ Calculus - Given an initial guess of x1 = 1, use the Newton-Raphson Method...
- numerical methods - Consider a spherical storage tank containing oil. The tank ...
- Calculus 1 Newton's Method - Using Newton's method, approximate the root of the ...
- Math - Hi, thanks for help in advance. Using the Equation: f(w) = 10/w - 0.77ln(...
- Math - Solving Trig Equations - Solve each equation for 0 is less than and equal...
- college math - hello i just want a answer in these question: please. im begging...
- Maths - i NEED TO TURN (7X-3)^1/3 INTO AN ITERVATIVE FORMULA USING THE NEWTON ...