Posted by Jasmin on Wednesday, November 16, 2011 at 12:58am.
Fx Applied = k*x
(k=5.8x10^4)
Vf=Vo+A(Xf-Xo)
Fo=Po*A and Ff=Pf*A
Po=kXo/A and Pf=kXf/A
Tf=(Pf*Vf*To)/(Po*Vo)
Solve for Tf by plugging in the unknown values with the equations above.
It would look something like this...
Tf=(kxf/a)*(Vo+A(delta x))*(To)/(kxo/A)(Vo)
Related Questions
Physics - The drawing shows an ideal gas confined to a cylinder by a massless ...
Thermodynamics - 3. A gas is confined in a 0.47-m-diameter cylinder by a piston...
Physics - Suppose a monatomic ideal gas is contained within a vertical cylinder ...
Physics - Suppose a monatomic ideal gas is contained within a vertical cylinder ...
Physics - 4) A 10 cm cylinder chamber has a 5cm diameter piston attached to one ...
Physics - A gas is confined in a 0.47-m-diameter cylinder by a piston, on which ...
Physics HELP!!!!!!!! - Suppose a monatomic ideal gas is contained within a ...
physics - A movable piston having a mass of 8.00 kg and a cross-sectional area ...
physics - A piston-cylinder assembly with the piston resting on a set of stops, ...
Physics - A movable piston having a mass of 7.26 kg and a cross-sectional area ...
For Further Reading