posted by Kristi on .
How many grams of CO2 would be produced from the following reaction sequence?
HI + KHCO3 -> KI + H2CO3
H2CO3 -> H2O + CO2
if 20.0 ml of 1.00 M KHCO3 solution is mixed with 20.0 ml of 1.50 M HI solution.
20 mL x 1.00M KHCO3 = 20 millimoles.
20 mL x 1.50M HI = 30 mmoles.
This is a 1:1 reaction (1 mole HI reacts with 1 mole KHCO3); therefore, the limiting reagent is KHCO3. Thus 20 mmoles H2CO3 will be produced (0.020 moles) which will produce 0.020 moles CO2.
grams = moles x molar mass.
0.88 g CO2