A force of 10N is used to lift 600-kg ball from the ground to the a height of 1.8m when it is let go. What is the speed of the bal when it is let go?

To find the speed of the ball when it is let go, we can use the principle of conservation of energy. The initial potential energy of the ball is equal to the final kinetic energy of the ball.

Step 1: Calculate the potential energy of the ball at the starting point.
Potential energy (PE) is given by the formula: PE = m * g * h, where m is the mass, g is the acceleration due to gravity, and h is the height.
In this case, m = 600 kg, g = 9.8 m/s^2, and h = 1.8 m.
PE = 600 kg * 9.8 m/s^2 * 1.8 m = 10,584 J

Step 2: Calculate the kinetic energy of the ball when it is let go.
Kinetic energy (KE) is given by the formula: KE = 1/2 * m * v^2, where m is the mass and v is the velocity.
In this case, we need to find v.
We know that the potential energy at the starting point is equal to the kinetic energy at the final point, so:
PE = KE
10,584 J = 1/2 * 600 kg * v^2

Step 3: Solve for v.
Rearrange the equation to solve for v:
v^2= (2 * 10,584 J) / 600 kg
v^2 = 35.28 m^2/s^2
v ≈ √(35.28) ≈ 5.94 m/s

Therefore, the speed of the ball when it is let go is approximately 5.94 m/s.