Wednesday

April 16, 2014

April 16, 2014

Posted by **Anonymous** on Tuesday, November 15, 2011 at 4:59pm.

- calculus -
**Steve**, Tuesday, November 15, 2011 at 6:28pmBy inspection, the curves intersect at (1,1) and (1,-1)

ellipse: 4x + 6yy' = 0

y' = -2x/3y

at (1,1) slope = -2/3

at (1,-1) slope = 2/3

semicubical parabola: 2yy' = 3x^2

y' = 3x/2y

at (1,1) slope = 3/2

at (1,-1) slope = -3/2

The slopes at the intersections are negative reciprocals; hence the curves are orthogonal.

**Related Questions**

calculus - if the tangent of two intersecting circles, at their points of ...

maths - determine the co-ordinate of the poin of intersection of the curves y=x*...

Advanced Functions - Identify the point of intersection of these two curves: P(t...

Calculus - Find the area between the two curves y1= x^2 - 4x + 5 and y2 = 2x - 3...

calculus - Two commercial airplanes are flying at an altitude of 40,000 ft ...

Math - Mark each of the following True or False. ___ a. All vectors in an ...

CALCULUS ONE! - The graph of sinx and cosx intersect once between 0 and pi/2. ...

Calculus-check my answers please - dy/dx= (y^2 -1)/x 1. Give the general ...

Calculus - Explain fully please and thank you! =) Determine the point of ...

calculus - Find the points of intersection of the curves y=2sin(x-3) and y=-4x^2...