Friday

October 24, 2014

October 24, 2014

Posted by **Anonymous** on Tuesday, November 15, 2011 at 4:59pm.

- calculus -
**Steve**, Tuesday, November 15, 2011 at 6:28pmBy inspection, the curves intersect at (1,1) and (1,-1)

ellipse: 4x + 6yy' = 0

y' = -2x/3y

at (1,1) slope = -2/3

at (1,-1) slope = 2/3

semicubical parabola: 2yy' = 3x^2

y' = 3x/2y

at (1,1) slope = 3/2

at (1,-1) slope = -3/2

The slopes at the intersections are negative reciprocals; hence the curves are orthogonal.

**Answer this Question**

**Related Questions**

calculus - if the tangent of two intersecting circles, at their points of ...

Math - Mark each of the following True or False. ___ a. All vectors in an ...

Calculus - Orthogonal Trajectories - Find the orthogonal trajectories of the ...

maths - determine the co-ordinate of the poin of intersection of the curves y=x*...

calculus - Show that the curves (y= √2sinx) and (y=√2cosx) intersect...

Calculus - show that the curves r=asin(è) and r=acos(è) intersect at right ...

Calculus-check my answers please - dy/dx= (y^2 -1)/x 1. Give the general ...

Math - I'm doing a bunch of practice finals and I don't know how to approach ...

Advanced Functions - Identify the point of intersection of these two curves: P(t...

calculus - Two commercial airplanes are flying at an altitude of 40,000 ft ...