Wednesday

December 17, 2014

December 17, 2014

Posted by **Celee** on Tuesday, November 15, 2011 at 4:52pm.

- statistics permutations and combinations -
**Reiny**, Tuesday, November 15, 2011 at 6:12pm3 cases :

2 women, 2 men ---> C(7,2)xC(5,2) = 21(10) = 210

3 women, 1 man ---> C(7,3)xC(5,1) = 35(5) = 175

4 women, 0 men ---> C(7,4) = 35

add up the 4 cases to get 420

or, exclude the case of no women, and one woman

C(12,4) - C(7,1)xC(5,3) - C(7,0)x(C5,4)

= 495 - 70 - 5 = 420

**Answer this Question**

**Related Questions**

statistics - Suppose that a department contains 8 men and 20 women. How many ...

math - In how many ways can a committee of five people be selected from seven ...

math - In how many ways can a committee of five people be selected from seven ...

math prob - A committee of 5 people is selected from a group of 7 men and 9 ...

math - A department contains 13 men and 20 women. How many ways are there to ...

math - Suppose that a department contains 11 men and 19 women. How many ways are...

Discreate Math - Suppose that a department contains 13 men and 19 women. How ...

discrete math - Suppose that a department contains 10 men and 17 women. How many...

discrete math - Suppose that a department contains 10 men and 17 women. How many...

maths - How can I select a committee of 5 people out of 10 men and 8 women. ...