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November 28, 2015
Posted by **Celee ** on Tuesday, November 15, 2011 at 4:52pm.

- statistics permutations and combinations -
**Reiny**, Tuesday, November 15, 2011 at 6:12pm3 cases :

2 women, 2 men ---> C(7,2)xC(5,2) = 21(10) = 210

3 women, 1 man ---> C(7,3)xC(5,1) = 35(5) = 175

4 women, 0 men ---> C(7,4) = 35

add up the 4 cases to get 420

or, exclude the case of no women, and one woman

C(12,4) - C(7,1)xC(5,3) - C(7,0)x(C5,4)

= 495 - 70 - 5 = 420