A rolaids tablet contains calcium carbonate which neutralizes stomach acid. If rolaids tablet neutralizes 42.15 mL of 0.320M hydrochloric acid, how many milligrams of calcium carbonate are in a Rolaids tablet

CaCO3 + 2 HCl ------> CaCl2 + H2O + CO2
Pls show steps

mols HCl used = M x L = ?

Now use the coefficients in the balanced equation to convert moles HCl to moles CaCO3. moles HCl x (1 mole CaCO3/2 moles HCl) = ?moles HCl x 1/2 = xx moles CaCO3.
grams CaCO3 = moles x molar mass and convert to mg.

To find the number of milligrams of calcium carbonate in a Rolaids tablet, we can use the balanced chemical equation given and the stoichiometry of the reaction.

First, let's determine the number of moles of hydrochloric acid (HCl) that were neutralized:

Moles of HCl = concentration of HCl × volume of HCl
= 0.320 mol/L × 0.04215 L
≈ 0.0135 mol

According to the balanced equation, each mole of calcium carbonate (CaCO3) reacts with 2 moles of hydrochloric acid (HCl). Therefore, the number of moles of calcium carbonate in the tablet can be determined as:

Moles of CaCO3 = 0.0135 mol ÷ 2
= 0.00675 mol

Since the molar mass of calcium carbonate (CaCO3) is 100.1 g/mol, we can calculate the mass of calcium carbonate in grams:

Mass of CaCO3 = Moles of CaCO3 × molar mass of CaCO3
= 0.00675 mol × 100.1 g/mol
≈ 0.675 g

To convert grams to milligrams, we multiply by 1000:

Mass of CaCO3 in milligrams = 0.675 g × 1000
= 675 mg

Therefore, there are approximately 675 milligrams of calcium carbonate in a Rolaids tablet.