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March 27, 2015

March 27, 2015

Posted by **jjena** on Tuesday, November 15, 2011 at 6:11am.

Picture the Problem: We can find q from 1=2 PI(delta E\E)cycle and then ise this result to find the width of the resonance deltaw=w\Q.The resonance frequency is the natural frequency.The amplitude can be found from Equation 14-49 both at resonance and off resonance with damping contant caculated from Q using Equation 14-41 in the from b=w0m\Q

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