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April 18, 2014

April 18, 2014

Posted by **vmu** on Tuesday, November 15, 2011 at 2:34am.

Z divied by Z+2+i=3+i

- maths -
**Reiny**, Tuesday, November 15, 2011 at 8:15amZ/(Z+2+i) = 3+i

Z = 3Z + Zi + 6 + 2i + 3i + i^2

Z - 3Z - iZ = i^2 + 5i + 6

Z(-2-i) = i^2 + 5i + 6

Z = -(i^2 + 5i + 6)/(i+2)

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