physics
posted by paul on .
A rocket is fired in deep space, where gravity is negligible. In the first second it ejects 1/160 of its mass as exhaust gas and has an acceleration of 15.1 m/s^2.What is the speed v_gas of the exhaust gas relative to the rocket?

A rocket is fired in deep space, where gravity is negligible. In the first second it ejects 1/160 of its mass as exhaust gas and has an acceleration of 15.1 m/s^2.What is the speed v_gas of the exhaust gas relative to the rocket?
By means of the rocket equation,
deltaV = cln(Wo/Wt) where
deltaV or dV = the incremental change in velocity over a given time period, Wo = the initial weight at ignition, Wt = the weight after a specific time period and c = the velocity of the exhaust gases. ln = the natural logarithm of.
After one second of firing, the rocket achieves a speed of 15.m/s.
Therefore,
dV = 15.1 = cln[Wo/(WoWo/160)
...= ]5.1 = cln[1/(11/160] = ............cln(1.006289)
15.1 = cln(1.006289)  c(.0062696
Hence, c = 2408m/s