Posted by **Ryan** on Monday, November 14, 2011 at 8:46pm.

Let a force of 1500 Newtons act through a distance of 200 meters on a 1500 kg car which starts from rest.

a. What is the work done?

b. What is the final velocity?

c. What is the car's momentum?

d. What is the car's change in momentum?

e. What is the car's Kinetic Energy?

f. What is the car's change in Kinetic Energy?

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**bobpursley**, Monday, November 14, 2011 at 8:58pm
workdone=force*distanc

1/2 mv^2=work done solve for v

momentum=mv

changemomentum=mv-m*0

KE= workdone=1/2mv^2

change in KE= 1/2 mv^2-1/2 m*0^2

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**fyu**, Saturday, November 3, 2012 at 10:36pm
78ghvo7

- physics -
**Anonymous**, Monday, March 10, 2014 at 11:11am
. A car moving at 35 m/s on dry pavement, skids to a stop over 175 m. What is the coefficient of friction between the car’s tires and the pavement?

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