Posted by Jared Smith on Monday, November 14, 2011 at 8:33pm.
I will do the first, then you do the remaining ones in the same way
sin t = -2/48 = -1/24 and cos t < 0
therefore t must be in quadrant III ( by CAST rule)
I make a triangle, the missing side is x
x^2 + 1^2 = 24^2
x = √575
then in III, cos t = -√575/24 = appr. -.999
or
take sin^-1 (+1/24) to get 2.388°
so in III , t = 180+2.388 = 182.388°
cos 182.388° = appr. -.999
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