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Posted by **Mattie** on Monday, November 14, 2011 at 8:16pm.

How would I simplify (2x^5 y^4 z^3/x^-1 y^5 z^5)^-1

Thank you for any help you can give me-I'm so stuck for my homeworkk tonight. I know I can bring up the negatives to top and negative to bottom to make them positive but besides that-I don't get it

- Algebra -
**Steve**, Tuesday, November 15, 2011 at 10:12amStart out with the fraction as written. The wherever there is a negative exponent, swap between numerator and denominator:

(2x^{5}y^{4}z^{3}/x^{-1}y^{5}z^{5})^{-1}

Invert the fraction:

= x^{-1}y^{5}z^{5}/2x^{5}y^{4}z^{3}

= y^{5}z^{}/2x^{}x^{}y^{}z^{}

= y^{}z^{}/2x^{}y^{}z^{}

Now subtract exponents, leaving the larger portion where it is:

yz^{}/2x^{}

- Algebra -
**Steve**, Tuesday, November 15, 2011 at 10:14amOops. Lost track of the exponents:

...

y^5 z^5 / 2x^5 x^1 y^4 z^3

y^5 z^5 / 2x^6 y^4 z^3

yz^2/2x^6

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