A shopper in a supermarket pushes a loaded
31 kg cart with a horizontal force of 12 N.
The acceleration of gravity is 9.81 m/s2 .
a) Disregarding friction, how far will the
cart move in 3.6 s, starting from rest?
Answer in units of m
see other post.
To find the distance the cart will move in 3.6 seconds, we can use the formula for linear motion:
d = (1/2) * a * t^2
Where:
d is the distance traveled
a is the acceleration
t is the time
In this case, the cart starts from rest, so its initial velocity (v₀) is zero. The force applied by the shopper (F) is given as 12 N, and the mass of the cart (m) is 31 kg.
First, we need to find the acceleration (a) using Newton's second law of motion:
F = m * a
Plugging in the values, we get:
12 N = 31 kg * a
So, the acceleration is:
a = 12 N / 31 kg
Next, we can substitute the values of acceleration and time into the distance formula:
d = (1/2) * (12 N / 31 kg) * (3.6 s)^2
Calculating this equation will give us the distance traveled by the cart in 3.6 seconds.