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November 28, 2014

November 28, 2014

Posted by **Samantha** on Monday, November 14, 2011 at 4:02pm.

- Math -
**Steve**, Tuesday, November 15, 2011 at 9:46amLet the object be placed x feet from the weaker source. Then

ks/x^2 = k(4s)/(11-x)^2

or

4x^2 = (11-x)^2

4x^2 = 121 - 22x + x^2

3x^2 + 22x -121 = 0

(x+11)(3x-11) = 0

BRIGHT_____x__WEAK

8'4" -- 3'8"

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