Posted by **Jasmine** on Sunday, November 13, 2011 at 10:15pm.

A square conducting loop with sides of length L is rotation at a constant angular speed of, w (omega), in a uniform magnetic field of magnitude B. At time t=0, the loop is oriented so that the direction normal to the loop is aligned with the magnetic field. Find the expression for the potential difference induced in the loop as a function of time.

I think it's Vind= BL^2*w*sin(theta)

Is this right? If it's not, can someone please explain how it should be? Thanks.

## Answer This Question

## Related Questions

- Physics - A square conducting loop with sides of length L is rotation at a ...
- Physics - A square conducting loop with sides of length L is rotation at a ...
- Physics - A square conducting loop with sides of length L is rotation at a ...
- PHYSICS - A circular loop of flexible iron wire has an initial circumference of ...
- physics - A rectangular wire loop of dimensions a×b, with a=3.5 cm and b=4.5 cm...
- physics - A square loop of wire of side 2.8 cm carries 3.0 A of current. A ...
- Physics - A square loop of wire of side 3.0 cm carries 3.0 A of current. A ...
- physics EM - Shrinking Loop. A circular loop of flexible iron wire has an ...
- magnetic field - A square loop with resistance R=0.001 Ohms,mass 1.0 gram, and ...
- physics - A rectangular loop of wire with sides 0.196 and 0.584 m lies in a ...

More Related Questions