Posted by Shellby on Sunday, November 13, 2011 at 8:47pm.
Since these are the same masses, you can simply take the average of 90 and 10.
(90+10)/2 = 50. If they are not the same mass it is a little more complicated than that but all of these can be solved the same way.
heat gained by cool water + heat lost by warm water = 0
[mass cool H2O x specific heat H2O x (Tfinal-Tinitial)] + [mass warm H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Solve for Tfinal.
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