Posted by Suchi on Sunday, November 13, 2011 at 8:44pm.
I will assume you meant to state that they left at the same time.
Let the distance covered by the southbound be x
let the distance covered by the northbound be 272-x
time for southbound = x/68
time for northbound = (272-x)/71
solve: x/68 = (272-x)/71
71x = 18496 - 68x
139x = 18496
x = 133.06
the southbound car went 133.06 , and the northbound went 138.94 miles when they met
time = 133.06/68 = 1.957 hrs
( check: 138.94/71 = 1.957 hrs )
Just follow the instructions for the remaining part of the question.
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