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October 25, 2014

October 25, 2014

Posted by **Sarah** on Sunday, November 13, 2011 at 7:38pm.

- calculus -
**Reiny**, Sunday, November 13, 2011 at 8:49pmLet the point of contact of the rectangle in the first quadrant be (x,y)

then the base of the rectangle is 2x and the height is y

Area = 2xy

= 2x(2-x^2)

= 4x - 2x^3

d(Area)/dx = 4 - 6x^2

= 0 for a max of Area

6x^2 = 4

x^2 = 4/6

x = ±2/6

then height = y = 2 - 4/6 = 4/3

= 1.33 to the nearest hundreth

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