Posted by **Bill** on Sunday, November 13, 2011 at 4:01pm.

A 5.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/°C · g) and a 10.00-g sample of iron pellets (specific heat capacity = 0.45 J/°C · g) are heated to 100.0°C. The mixture of hot iron and aluminum is then dropped into 91.9 g of water at 23.7°C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings.

## Answer This Question

## Related Questions

- Chemistry - A 5.00 gram sample of aluminum pellets (specific heat capacity = 0....
- chemistry - a 5.00g sample of Al pellets (specific heat=0.89J/oC*g) and a 10.00g...
- CHEM - A 5.00 g sample of Al pellets (specific heat = .89 J/g degrees c) and a ...
- Science-Chemistry - A 5.00 g sample of Al pellets (specific heat = .89 J/g ...
- CHEM - A 5.00 g sample of Al pellets (specific heat = .89 J/g degrees c) and a ...
- intro chem HELp please - 1. Zinc is often used to calibrate calorimeters because...
- chemisty - A 5.10-g sample of iron is heated from 36.0 C to 75.0 C. The amount ...
- Chemistry - A 54.7-g sample of aluminum at 95.0°C is dropped into 35.0 g of ...
- CHEM - A 5.10-g sample of iron is heated from 36.0oC to 75.0oC. The amount of ...
- Lauren - The amount of heat required to raise temperature of 55.85 g of iron 1 ...

More Related Questions