Posted by Bill on .
A 5.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/°C · g) and a 10.00-g sample of iron pellets (specific heat capacity = 0.45 J/°C · g) are heated to 100.0°C. The mixture of hot iron and aluminum is then dropped into 91.9 g of water at 23.7°C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings.
heat lost by Al + heat lost by Fe + heat absorbed by water = 0
[mass Al x specific heat Al x (Tfinal-Tinitial)] + [mass Fe x specific heat Fe x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0. Solve for Tfinal.