Posted by **Anonymous** on Sunday, November 13, 2011 at 3:54pm.

What is the rotational inertia of a solid iron disk of mass 45 kg, with a thickness of 3.44 cm and radius of 19.0 cm, about an axis through its center and perpendicular to it?

- Physics -
**Damon**, Sunday, November 13, 2011 at 4:42pm
r = .19 meter

I = (1/2) m r^2 is moment of inertia of disk

I = (1/2)(45)(.19)^2

That is the rotational moment of inertia, I suspect what you want. If you really want the rotational inertia you must multiply that by omega, the angular velocity in radians per second.

## Answer this Question

## Related Questions

- physics (please check work) - Four identical particles, each with mass m, are ...
- Physics - The moment of inertia of an object depends on the shape of the object...
- physics - The uniform solid block in Fig. 11-36 has a mass of M = 5.60 kg and ...
- Physics - Pendulums - A uniform circular disk whose radius R is 32.0 cm is ...
- phys - A disk with a rotational inertia of 2.0 kg.m^2 and a radius of 0.40 m ...
- pysics - Consider a 6·kg disk with a radius of 0.6·m and rotating about an axis ...
- physics helpppp - Figure 10-35a shows a disk that can rotate about an axis at a ...
- physics - Consider a 9·kg disk with a radius of 0.9·m and rotating about an axis...
- physics - A curcial part of a piece of machinery starts as a flat uniform ...
- Physics - A solid circular disk has a mass of 1.67 kg and a radius of 0.144 m. ...

More Related Questions