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December 20, 2014

December 20, 2014

Posted by **Carol** on Sunday, November 13, 2011 at 1:10am.

For the following information, I understand 5(x+y) = 3000 for 1st plane & 10(x-y) = 3000 for 2nd plane.

When an airplane flies with a given wind, it can travel 3000 km in 5hrs. When the same airplane flies in the opposite direction against the wind it takes 10hrs to fly the same distance. Find the speed of the plane in still air and the speed of the wind.

- Pre-Algebra -
**Henry**, Monday, November 14, 2011 at 6:05pmVp + Vw = 3000km/5h = 600km/h.

Vp - Vw = 3000km/10h = 300km/h.

Add the 2 Eqs:

Eq1: Vp + Vw = 600.

Eq2: Vp - Vw = 300.

Sum: 2Vp = 900,

Vp = 450km/h = Speed in still air

In Eq1, substitute 450 for Vp:

450 + Vw = 600,

Vw = 150km/h. = Speed of wind.

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