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November 1, 2014

November 1, 2014

Posted by **Carol** on Sunday, November 13, 2011 at 1:10am.

For the following information, I understand 5(x+y) = 3000 for 1st plane & 10(x-y) = 3000 for 2nd plane.

When an airplane flies with a given wind, it can travel 3000 km in 5hrs. When the same airplane flies in the opposite direction against the wind it takes 10hrs to fly the same distance. Find the speed of the plane in still air and the speed of the wind.

- Pre-Algebra -
**Reiny**, Sunday, November 13, 2011 at 9:36amDivide your first equation by 5 to get : x+y = 600

Divide your 2nd equation by 10 to get: x-y = 300

add them: 2x = 900

x = 450

sub that back into your new 1st

450 + y = 600

y = 150

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