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November 25, 2014

November 25, 2014

Posted by **Kong** on Saturday, November 12, 2011 at 10:30pm.

a) 3 log x with base 8 + 2 = 0

b)2 log (x-1)with base 6 =log 4 with base 6

- Maths(logarithmic functions) -
**Reiny**, Sunday, November 13, 2011 at 1:12ama)

3 log_{8}x = -2

log_{8}x = -2/3

8^(-2/3) = x

x = 1/4

b) 2 log_{6}(x-1) = log_{6}4

log_{6}(x-1)^2 = log_{6}4

(x-1)^2 = 4

x-1 = ±2

x = 3 or x = -1 , but for log(x-1) to be defined, x>1

so x = 3

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