Posted by **mz tee** on Saturday, November 12, 2011 at 9:32pm.

solve the equation in the complex number system

x^4+x^3+4x^2+10x-60=0

- precalculus -
**Damon**, Saturday, November 12, 2011 at 10:00pm
try x = 2

16+8+16 +20 - 60 = 0 sure enough x = 2 works

so divide by (x-2)

x^3 + 3 x^2 + 10 x + 30

write as

x^3+10 x +3(x^2 +10)

x(x^2+10) + 3(x^2+10)

(x+3)(x^2+10)

so

x = -3 is a root

left with x^2 = -10

x = +/- i sqrt(10)

so

2, -3, i sqrt 10 , -i sqrt 10

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