Homework Help: physics

Posted by Andrew on Saturday, November 12, 2011 at 2:28pm.

1. You are planning to build a mini hydro power plant. A river near your home is w = 4.0 m wide and h = 1.0 m deep. You measure the water flow to be v = 1.50 m/s over the brink of a waterfall H = 10.0 m high. The company that makes the turbine advertises e = 25% efficiency in converting the potential energy of the water into electric energy. Derive an expression for the generated power in terms of the above variables and any physics constants. How many 100watts bulbs will this power handle?

physics - HerbvanH, Sunday, November 13, 2011 at 2:32pm
4 x 1 x 1.5 = 6 cubic meters of water per second = 6000 liters of water = 6000 kilos of water

amount of potential energy = m*g*h

E = 6000 * 9.81 * 10 = 588600 joules

25% efficiency => 147150 joules of energy

1 Watt = 1 joule / second

147150 / 100 = 1471.5 bulbs
physics - HerbvanH, Sunday, November 13, 2011 at 2:32pm
4 x 1 x 1.5 = 6 cubic meters of water per second = 6000 liters of water = 6000 kilos of water

amount of potential energy = m*g*h

E = 6000 * 9.81 * 10 = 588600 joules

25% efficiency => 147150 joules of energy

1 Watt = 1 joule / second

147150 / 100 = 1471.5 bulbs
physics - HerbvanH, Sunday, November 13, 2011 at 2:32pm
4 x 1 x 1.5 = 6 cubic meters of water per second = 6000 liters of water = 6000 kilos of water

amount of potential energy = m*g*h

E = 6000 * 9.81 * 10 = 588600 joules

25% efficiency => 147150 joules of energy

1 Watt = 1 joule / second

147150 / 100 = 1471.5 bulbs
physics - ooglaboogla, Sunday, November 13, 2011 at 9:15pm
this is wrong^

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