Posted by Andrew on .
1. You are planning to build a mini hydro power plant. A river near your home is w = 4.0 m wide and h = 1.0 m deep. You measure the water flow to be v = 1.50 m/s over the brink of a waterfall H = 10.0 m high. The company that makes the turbine advertises e = 25% efficiency in converting the potential energy of the water into electric energy. Derive an expression for the generated power in terms of the above variables and any physics constants. How many 100watts bulbs will this power handle?

physics 
HerbvanH,
4 x 1 x 1.5 = 6 cubic meters of water per second = 6000 liters of water = 6000 kilos of water
amount of potential energy = m*g*h
E = 6000 * 9.81 * 10 = 588600 joules
25% efficiency => 147150 joules of energy
1 Watt = 1 joule / second
147150 / 100 = 1471.5 bulbs 
physics 
ooglaboogla,
this is wrong^