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Chemistry

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a diver exhales a bubble with a volume of 250mL at a pressure of 2.4atm and a temp. of 15*C. How many gas particles are in this bubble?

  • Chemistry - ,

    Use PV = nRT and solve for n = number of moles.
    Then remember 1 mole of a gas contains 6.022E23 molecules.

  • Chemistry - ,

    so is it 2.9 E26??

  • Chemistry - ,

    If you had shown your work I could find your error.
    PV = nRT or n = PV/RT
    n = (2.4atm x 0.25L)/(0.08206L*atm x 288 K) = 0.0254 moles.
    0.0254 moles x 6.022E23 = approximately 1.5E22 molecules.

  • Chemistry - ,

    k thanks so much for your help!

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