Thursday
March 23, 2017

Post a New Question

Posted by on Friday, November 11, 2011 at 6:37pm.

a diver exhales a bubble with a volume of 250mL at a pressure of 2.4atm and a temp. of 15*C. How many gas particles are in this bubble?

  • Chemistry - , Friday, November 11, 2011 at 8:08pm

    Use PV = nRT and solve for n = number of moles.
    Then remember 1 mole of a gas contains 6.022E23 molecules.

  • Chemistry - , Friday, November 11, 2011 at 8:37pm

    so is it 2.9 E26??

  • Chemistry - , Friday, November 11, 2011 at 9:48pm

    If you had shown your work I could find your error.
    PV = nRT or n = PV/RT
    n = (2.4atm x 0.25L)/(0.08206L*atm x 288 K) = 0.0254 moles.
    0.0254 moles x 6.022E23 = approximately 1.5E22 molecules.

  • Chemistry - , Friday, November 11, 2011 at 10:03pm

    k thanks so much for your help!

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question