Posted by Mishaka on Friday, November 11, 2011 at 4:50pm.
Find the three zeros for the following function on the interval -5 </= x </= 5
(1 + 50sin(x)) / (x^2 + 3)
- Calculus - Reiny, Friday, November 11, 2011 at 5:12pm
For the expression to be zero,
1 + 50sinx = 0
sinx = -1/50
x = π +.02 or 2π - .02
x = 3.1616 or 6.263
the period of 50sinx is 2π, so adding or subtracting 2π to the above answers will produce more answers
3.1616+2π ---> beyond domain
3.1616-2π = -3.1216
6.263-2π = -.02
so for -5 ≤ x ≤ 5
x = -3.1216 , -.02, 3.1216
- Calculus - Mishaka, Friday, November 11, 2011 at 5:20pm
Thank you, this helps tremendously!
- Calculus - Mishaka, Friday, November 11, 2011 at 6:57pm
How did you come up with 3.1216 positive. I've tried to come up with this number but I can't figure it out. Also, it doesn't make 1 + 50 sin(x) = 0.
- Calculus - Reiny, Friday, November 11, 2011 at 9:43pm
It was a copy error.
As you can see from the 5th line, I had x = 3.1616
so the final answers are
x = -3.1216 , -.02, and 3.1616
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