Posted by **Tom** on Friday, November 11, 2011 at 11:30am.

considering that x is the independent variable in this equation:

y + y^3 + 3 = e^y^2 + 3^x * cos(3y) - x

Evaluate dy/dx

I get to:

dy/dx (1+3y) = e^y^2 * 3y^2 * dy/dx + 3^x * ln3 * (-sin(3y)) * 3 *dy/dx -1

Will it give me?

dy/dx(1+3y) =

dy/dx((e^y^2 * 3y^2) +

(3^x * ln3 * (-sin(3y)) * 3 ) -1

dy/dx(1+3y) =

dy/dx((e^y^2 * 3y^2) - (9^xsin(3y)ln3))

-1

1 / ((e^y^2 * 3y^2) - (9^xsin(3y)ln3) - (1+3y))

## Answer this Question

## Related Questions

- Stats - In each of the four examples listed below, one of the given variables is...
- Adult Development and life Assessment - What do we call the variable that is ...
- Adult Development and life Assessment - What do we call the variable that is ...
- pre calculus - evaluate if possible the function at the given values(s) of the ...
- calculus - evaluate if possible the function at the given values(s) of the ...
- MATH - Differential equations, initial value problem. The general equation of ...
- college Psychology - I am having trouble describing the interaction (How does ...
- biology need help - Which variable does the scientists or you deliberately ...
- biology - Which variable does the scientists or you deliberately change? ...
- math - 8 divided by 3 plus 6= You asked 8 divided by 3 plus 6= (8/3) + 6 = 2(2/3...

More Related Questions