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Help- Physics

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How much work did the movers do (horizontally) pushing a 130kg crate 10.1 m across a rough floor without acceleration, if the effective coefficient of friction was 0.50?

  • Help- Physics - ,

    Wc = 130kg * 9.8N/kg = 1274N.

    Fc = 1274N @ 0deg.
    Fp = 1274sin(0) = 0 = Force parallel to
    floor.
    Fv = 1274cos(0) = 1274N. = Force perpendicular to floor.

    Ff = u*Fv = 0.5 * 1274 = 637N. = Force
    of friction.

    Fn = Fap - Fp - Ff = ma = 0. a = 0.
    Fap - 0 - 637 = 0,
    Fap = 637N. = Force applied.

    Work = Fd = 637 * 10.1 = 6434J.

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