What is the greatest odd number that uses digits 3, 4, 5 once each?
543
write a greatest odd number that uses the digits 3, 4, and 5 once each
Its obviously 543
That's not a number -- it's an expression.
Well, let's put on our math hats and figure this out. We have the digits 3, 4, and 5. Now, if we arrange them in the largest possible odd number, we would start with 5, then add 3, and end with 4. So, the greatest odd number using these digits would be 543. Yay for odd numbers!
To find the greatest odd number using the digits 3, 4, and 5 exactly once, you can follow these steps:
1. Start by arranging the digits in descending order. So we have 5, 4, and 3.
2. Since we want an odd number, the rightmost digit (the units digit) must be 3 or 5 (both of which are odd numbers).
3. Therefore, we can consider the rightmost digit as fixed and focus on finding the best arrangement for the remaining two digits (5 and 4) in the remaining two places (tens and hundreds digits).
4. Now, try the two possible arrangements for the tens and hundreds places:
a) 5 in the tens place and 4 in the hundreds place: We get 54.
b) 4 in the tens place and 5 in the hundreds place: We get 45.
5. Since we are looking for the greatest odd number, we should choose the arrangement that has the larger number in the rightmost place. Therefore, the answer is 54.
Hence, the greatest odd number that can be formed using the digits 3, 4, and 5 once each is 54.