The way this system works is that you should have typed your response at the old question. I don't remember the numbers well enough. Anyway, look at your original post; I've given detailed work there.
How many grams of NaOh are required to neutralize 15.0mL 0f 0.85M HCl. Show calculations please
Of course! I'll be happy to explain how to perform the calculations for your previous question. However, since I don't have access to your previous question, please provide me with the necessary details so that I can assist you properly.
