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Posted by on Friday, November 11, 2011 at 12:48am.

A constant torque of 27.2 N · m is applied to
a grindstone for which the moment of inertia
is 0.158 kg · m2.
Find the angular speed after the grindstone
has made 18 rev.
Assume the grindstone
starts from rest.
Answer in units of rad/s

  • Physics - , Friday, November 11, 2011 at 4:45am

    a = 27.2/.158 = 172 radians/second^2
    18*2pi= 0 + 0t + (1/2)(172)t^2
    113 = 86 t^2
    t = 1.15 seconds

    w = 0 + a t
    w = 172*1.15 = 197 radians/second

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