Posted by steph on Thursday, November 10, 2011 at 10:20pm.
600 feet total fence
3 sides of x feet
remaining side: 600 - 3x
a(x) = x(600-3x) = 3x(200-x)
naturally, 3x < 600, so x < 200 assuming an infinitesimally thin fence and poles of zero diameter. :-)
22500 = 3x(200-x)
-3x^2 + 600x - 22500 = 0
x = 50 or 150
max area achieved at x = 100
a(100) = 30,000
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