Homework Help: chemistry

Posted by Monique on Thursday, November 10, 2011 at 8:35pm.

a 25.0ml dsmplr og 0.105M HCI was titrated with 31.5ml of NaOH. What is the concentration of the NaOH
I got 0.0834M am I correct
HCI + NaOH -----> H20 + NaCl
25.0ml HCI x 1L/1000mlx0.105 mol HCI/1L HCI X 1 mol NaOH/ I mol HCI = 0.0834M

chemistry - DrBob222, Thursday, November 10, 2011 at 11:42pm
My calculator reads 0.0833333 which I would round to 0.0833 and not 0.0834.

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