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October 22, 2014

October 22, 2014

Posted by **steph** on Thursday, November 10, 2011 at 8:10pm.

a)how high was the frog when its horizontal distances from the base of the box was 2 feet?

b)at what two horizontal distances from the base of the box was the frog 3.25 feet above the ground?

c)at what horizontal distance from the base of the box did the frog reach its highest point?

d) what was the maximum height reached by the frog?

- pre-calc -
**Steve**, Friday, November 11, 2011 at 10:26amh(x)=-0.5x^2+1.25x+3

h(2) = 3.5

3.25 = -0.5x^2+1.25x+3

-0.5x^2+1.25x-.25 = 0

x = .22 (going up) or 2.28 (coming down)

a parabola reaches its vertex when x = -b/2a = -1.25/-1 = 1.25

h(1.25) = 3.781

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