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April 16, 2014

April 16, 2014

Posted by **Ashley** on Thursday, November 10, 2011 at 8:08pm.

I know that the speed of the balloon is

the square root of (10)^2 + (5)^2, but I was wondering if someone could tell me why the speed is equal to that. Thanks.

- Please Help!!!!!! -
**Steve**, Friday, November 11, 2011 at 12:03amEvery second the balloon rises 10 ft and moves sideways 5 feet.

So, the distance traveled in one second is sqrt(10^2 + 5^2)

Since it traveled that distance in one second, and speed is distance/time, the same triangle can be used to calculate the speed.

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