Post a New Question


posted by .

Find the volume V of the described solid S.
The base of S is a circular disk with radius 2r. Parallel cross-sections perpendicular to the base are squares.

  • calculus -

    I may have this wrong, but here's how I see it:

    Draw a circle of radius 2r. That's the base. Draw a chord perpendicular to the x-axis at distance x from the center. At this point,

    x^2 + y^2 = 4r^2

    Now, erect a square of height 2y on the base. That is a cross-section of the solid. It has area 4y^2

    The volume is thus Int(4y^2 dx)[0,2r]
    But, y^2 = 4r^2 - x^2

    v = 4*Int(4r^2 - x^2) dx)[0,2r]
    = 4*(4r^2 x - 1/3 x^3)[0,2r]
    = 4(8r^3 - 8r^3/3)
    = 32(2/3 r^3)
    = 64/3 r^3

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question