math
posted by muma .
Simplify:
(a) 4ã7 (2ã3 +3ã6 ã7 )
(b) (3ã7 ã2 )squared
(c) (16ã24)/(4ã96)
(d) 7/(ã20 )  4/(ã12)
(e) (3ã2)/(ã12)  (5ã3)/(ã8 )

I will assume your ã is supposed to be a √
To do these, you should know the basic laws for radicals, such as
√a x √b = √(ab) etc.
I will do the first and last, give the others a shot
a)
4√7(2√3 + 3√6  √7)
= 8√21 + 12√42  4√49
= 8√21 + 12√42  28
e)
3√2/√12  5√3/√8
= 3√2/(2√3)  5√3/(2√2)
= 3√2/(2√3)(√3/√3)  5√3/(2√2)(√2/√2)
= 3√6/6  5√6/4
= √6/2  5√6/4
= 2√6/4  5√6/4
= 3√6/4