Posted by Meron on Thursday, November 10, 2011 at 8:00am.
What is the zero of x^3+1/x^2-1 (my answer is -1. Is that correct?) please help
- Math - Reiny, Thursday, November 10, 2011 at 8:42am
If you meant
then if x = -1, your expression becomes 0/0 which is "indeterminate".
notice that (x^3+1)/(x^2-1)
= (x+1)(x^2 + x + 1)/((x+1)(x-1))
= (x^2 + x + 1)/(x-1)
I don't know if you know anything about limits, but
the limit of the above , as x --> - 1
= (1 - 1 + 1)/(-2) = -1/2
There are actually no zeros for this graph,
will show you.
the expression actually reduces to
y = (x^2 + x + 1)/(x-1) , which has a vertical asymptote at x=1
the original function
y = (x^3 + 1)(/(x^2-1) looks exactly the same except it would have a "hole" or missing point at (-1, -1/2)
- Math - Meron , Thursday, November 10, 2011 at 8:54am
Thank u so much!
Answer this Question
More Related Questions
- math,correction, bobpursly - Since when is 5^7 =8125? if a number is a multple ...
- Math - ok so i'm kinda sort of confused... I had this for a equation X^2 + 4X - ...
- maths - how do i solve this equation? there is another answer other than 0, but ...
- math help please - if the product of two whole numbers is zero, then one of the ...
- math,correction - can someone correct this for me parts A-E and if i am wrong ...
- math,correction,plz - Can someone who has a few minutes could you please correct...
- Economics - The market demand in a Bertrand duopoly is P = 15 - 4Q, and the ...
- MAth!PLease Help! - 5. Find the x and y intercepts of each linear equation. Be ...
- Calculus--> bobpursley - How do you get m=0? from taking the second ...
- Algebra - Hi this question was already asked but there is still no correct ...