Saturday

April 18, 2015

April 18, 2015

Posted by **Meron** on Thursday, November 10, 2011 at 8:00am.

- Math -
**Reiny**, Thursday, November 10, 2011 at 8:42amIf you meant

(x^3+1)/(x^2-1)

then if x = -1, your expression becomes 0/0 which is "indeterminate".

notice that (x^3+1)/(x^2-1)

= (x+1)(x^2 + x + 1)/((x+1)(x-1))

= (x^2 + x + 1)/(x-1)

I don't know if you know anything about limits, but

the limit of the above , as x --> - 1

= (1 - 1 + 1)/(-2) = -1/2

There are actually no zeros for this graph,

as

http://www.wolframalpha.com/input/?i=%28x%5E3%2B1%29%2F%28x%5E2-1%29

will show you.

the expression actually reduces to

y = (x^2 + x + 1)/(x-1) , which has a vertical asymptote at x=1

the original function

y = (x^3 + 1)(/(x^2-1) looks exactly the same except it would have a "hole" or missing point at (-1, -1/2)

- Math -
**Meron**, Thursday, November 10, 2011 at 8:54amThank u so much!

**Answer this Question**

**Related Questions**

math,correction, bobpursly - Since when is 5^7 =8125? if a number is a multple ...

Math - ok so i'm kinda sort of confused... I had this for a equation X^2 + 4X - ...

maths - how do i solve this equation? there is another answer other than 0, but ...

math help please - if the product of two whole numbers is zero, then one of the ...

math,correction - can someone correct this for me parts A-E and if i am wrong ...

math,correction,plz - Can someone who has a few minutes could you please correct...

Economics - The market demand in a Bertrand duopoly is P = 15 - 4Q, and the ...

MAth!PLease Help! - 5. Find the x and y intercepts of each linear equation. Be ...

Calculus--> bobpursley - How do you get m=0? from taking the second ...

Algebra - Hi this question was already asked but there is still no correct ...