an object of mass 150kg is pulled on a horizontal rough ground by a force of 900newton(N).find the coefficient of static friction (taken g=10m/s)
Cannot work, not enough information. Is the object at constant velocity?
I think the answer is: Fs=mg=150kg x 10m/s^2=1500N then Coefficient of sf=Fs/Fn = 1500N/900N =1.66
To find the coefficient of static friction, we need to understand the conditions for the object to remain in a state of rest while being pulled. In this case, the force of friction needs to balance the applied force in order for the object not to move.
Let's go step by step to find the coefficient of static friction:
1. Calculate the gravitational force (weight) acting on the object:
Weight = mass × gravity
= 150 kg × 10 m/s^2
= 1500 N
2. Determine the maximum force of static friction:
Force of friction (Ff) = applied force (Fa) × coefficient of static friction (μs)
3. Substitute the values into the equation:
900 N = Ff
4. Solve for the coefficient of static friction:
μs = Ff / Fa
= 900 N / 1500 N
= 0.6
Therefore, the coefficient of static friction (μs) is 0.6.