Sorry for repeated questions, but this is my last problem:
s = ut + 1/2(gt)
The "t" for "gt" is squared, and the subject of the formula is "u".
Thank you very much (and please include workings).
Sorry for wrong problem, it should be:
(1/2)*(gt)
when you want a variable to be squared you use this symbol, ^ , which means "raised to".
in the problem,
s = ut + (1/2)*(g*t^2)
s - (1/2)*(g*t^2) = ut
[ s - (1/2)*(g*t^2) ]/t = u, or
u = [ s - (1/2)*(g*t^2) ]/t
I bet you mean:
s = u t + (1/2) g t^2
which is a falling object with initial speed down u under gravitational acceleration g. s is distance.
s - (1/2) g t^2 = u t
u = [ s - (1/2) g t^2 ] /t
or
u = s/t - (1/2) g t
No problem at all! I'm here to help you with your questions.
To make "u" the subject of the formula, we need to isolate it on one side of the equation. Let's go through the steps to do that.
Here's the given equation:
s = ut + 1/2(gt^2)
To make "u" the subject, we need to isolate "ut" on one side of the equation. Start by subtracting 1/2(gt^2) from both sides of the equation:
s - 1/2(gt^2) = ut
Now, we want to isolate "u" by dividing both sides of the equation by "t":
(s - 1/2(gt^2)) / t = u
Therefore, the expression for "u" in terms of the other variables is:
u = (s - 1/2(gt^2)) / t
That's it! The subject of the formula is now "u". If you have specific values for "s", "g", and "t", you can plug them into this expression to find the value of "u".