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April 17, 2014

April 17, 2014

Posted by **ASDFGHJKL;** on Thursday, November 10, 2011 at 5:15am.

s = ut + 1/2(gt)

The "t" for "gt" is squared, and the subject of the formula is "u".

Thank you very much (and please include workings).

- Math -
**ASDFGHJKL;**, Thursday, November 10, 2011 at 5:19amSorry for wrong problem, it should be:

(1/2)*(gt)

- Math -
**Jai**, Thursday, November 10, 2011 at 6:51amwhen you want a variable to be squared you use this symbol, ^ , which means "raised to".

in the problem,

s = ut + (1/2)*(g*t^2)

s - (1/2)*(g*t^2) = ut

[ s - (1/2)*(g*t^2) ]/t = u, or

u = [ s - (1/2)*(g*t^2) ]/t

- Math -
**Damon**, Thursday, November 10, 2011 at 7:21amI bet you mean:

s = u t + (1/2) g t^2

which is a falling object with initial speed down u under gravitational acceleration g. s is distance.

s - (1/2) g t^2 = u t

u = [ s - (1/2) g t^2 ] /t

or

u = s/t - (1/2) g t

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