A = h/2 (a+b)
the subject of the given formula is "a" not "A"
please include workings (along with solution) thanks
this topic that i learned in class is "changing the subject of a formula" FYI
Use algebra to derive the formula for a in terms of h, A and b.
You should use parentheses to show if (a+b) is part of the denominator of a fraction h/[2(a+b)], or not. I will assume you mean
A = (h/2)*(a+b)
a + b = 2A/h
a = 2A/h -b
God bless you. Thanks!
To solve for "a" in the given formula:
A = h/2 (a+b)
Step 1: Expand the expression
First, distribute the h/2 to both terms inside the parentheses:
A = (h/2)a + (h/2)b
Step 2: Rearrange the terms
To isolate "a" on one side, move the (h/2)b term to the other side by subtracting it from both sides of the equation:
A - (h/2)b = (h/2)a
Step 3: Simplify the equation
To simplify, divide both sides of the equation by (h/2):
(A - (h/2)b) / (h/2) = a
Step 4: Simplify further
The division of A - (h/2)b by (h/2) can be expressed as:
A / (h/2) - ((h/2)b) / (h/2) = a
Simplifying further:
A / (h/2) - b = a
So, the subject of the given formula "A = h/2 (a+b)" is "a", and the solution is:
a = A / (h/2) - b