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October 25, 2014

October 25, 2014

Posted by **Sally** on Thursday, November 10, 2011 at 2:33am.

Compute the following probabilities.

a. Pr(X<10)

b. Pr(X<11.04)

I don't know where to start.

- Math -
**Reiny**, Thursday, November 10, 2011 at 8:26ama) P(X<10) gives a z-score of (10-10)/2 = 0

b) P(X<11.04) gives a z-score of (11.04-10)/2 = .52

You must be given a table of "normal distribution" or have access to a program that duplicates the table or chart.

I use this one

http://davidmlane.com/hyperstat/z_table.html

You can use it directly without finding the z-scores

e.g. for b)

1.

enter: mean: 10 , Sd: 2, click on below and enter 11.04 to get .698468

2.

enter: mean: 0 , Sd: 1 , click on "below" and enter the z-score of .52 to get .698468

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